$A$ graph between kinetic energy $K$ and momentum $P$ of a particle is plotted as shown in the figure. The mass of the moving particle is ........ $kg$.

$A$ running man has half the kinetic energy of a boy who has half the man's mass. The man speeds up by $1 \, m/s$ so that his kinetic energy becomes equal to that of the boy. The original speed of the man is:

$A$ man who is running has half the kinetic energy of a boy of half his mass. The man speeds up by $1 \,ms^{-1}$ and then has the same kinetic energy as the boy. The initial speed of the boy is

$A$ particle of mass $m_1$ is moving with a velocity $v_1$ and another particle of mass $m_2$ is moving with a velocity $v_2$. Both of them have the same momentum,but their kinetic energies are $E_1$ and $E_2$ respectively. If $m_1 > m_2$,then:

The kinetic energy of a body is increased by $4$ times. Its momentum will

Two masses of $1 \ g$ and $4 \ g$ are moving with equal kinetic energy. The ratio of the magnitudes of their momenta is